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Tan–1 1 3 sec 2 − − − is equal to

WebIn the first method, we used the identity sec 2 θ = tan 2 θ + 1 sec 2 θ = tan 2 θ + 1 and continued to simplify. In the second method, we split the fraction, putting both terms in … Webtanx= 3=tan 3π. Therefore, x= 3π∈[− 2π, 2π] Now let sec −1(−2)=y that is secy=−2. Therefore, y=−sec 3π that is. secy=sec(π− 3π)=sec 32π. Thus, y= 32π∈[0,π]−(2π) Now …

(tan^3A-1)/(tanA-1)=sec^2A+tanA prove? Socratic

WebTo evaluate compositions of the form f (g − 1 (x)), f (g − 1 (x)), where f f and g g are any two of the functions sine, cosine, or tangent and x x is any input in the domain of g − 1, g − 1, … WebThe value of tan −13−sec −1(−2) = 3π−sec −1(sec(π− 3π)) = 3π− 32π =− 3π Video Explanation Solve any question of Inverse Trigonometric Functions with:- Patterns of … mohammed reshid https://imagery-lab.com

tan−152 +tan−131 +tan−1121 =4π \\[ \\begin{array}{l} \\tan ^{-1 ...

WebRewrite sec(x) sec ( x) in terms of sines and cosines. Rewrite tan(x) tan ( x) in terms of sines and cosines. Multiply by the reciprocal of the fraction to divide by 1 cos(x) 1 cos ( x). Write … WebAll steps Final answer Step 1/3 Solution: c) 2 cos 2 θ − 7 cos θ = − 3 Explanation: First simplify the equation then apply the trigonometric properties Add 3 to both sides of the equation. 2 cos 2 ( θ) − 7 cos ( θ) + 3 = 0 Factor by grouping. ( 2 cos ( θ) − 1) ( cos ( θ) − 3) = 0 WebA trigonometric identity is an equation involving trigonometric functions that is true for all angles for which the functions are defined. We can use the identities to help us solve or simplify equations. The main trigonometric identities are listed next. Rule: Trigonometric Identities Reciprocal identities Pythagorean identities mohammed rizvi cricketer

tant 3-sei (-2) is equal to.[tex] tan {?}^{ - 1} \sqrt{3} - sec ...

Category:Question: 2cos2θ−7cosθ=−3 3tan3θ=tanθ secθ(2cosθ−2)=0 - Chegg

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Tan–1 1 3 sec 2 − − − is equal to

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WebPutting θ θ x = tan θ in the above expression we get, ⇒ tan [ sec - 1 1 + tan 2 ( θ)] θ θ θ θ θ θ ⇒ tan [ sec - 1 sec ( θ)] ∵ 1 + tan 2 ( θ) = sec 2 ( θ) θ θ ⇒ tan θ ⇒ x Therefore the value of tan [ sec - 1 1 + x 2] is x. Hence, the correct answer is Option (B). Suggest Corrections 1 Similar questions Q. Evaluate : ∫ 1 x ( 1 + log x) d x Q. WebAug 22, 2024 · Tant 3-sei (-2) is equal to. Advertisement Expert-Verified Answer 17 people found it helpful AnswEr : Given Expression, We know that, Therefore, We know that, tan …

Tan–1 1 3 sec 2 − − − is equal to

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WebMar 22, 2024 · For this first we calculate sec a and cos a We know that sec2 a = 1 + tan2 a sec a = √ (1+𝑡𝑎𝑛2 a) We convert tan−1 to sin−1 sec a = √ (1+𝑥2) 1/cos𝑎 = √ (1+𝑥2) 1/√ (1 + 𝑥^2 ) = cos𝑎 𝒄𝒐𝒔𝒂 = 𝟏/√ (𝟏 + 𝒙^𝟐 ) We know that sin a = √ ("1 – cos2 a" ) sin a = √ ("1 –" (1/√ (1 + 𝑥^2 ))^2 ) sin a = √ ("1 –" 1/ (1 + 𝑥2)) sin a = √ ( (1 + 𝑥2 − 1)/ (1 + 𝑥2)) = … WebSep 30, 2016 · Trigonometry Trigonometric Identities and Equations Proving Identities 1 Answer George C. Oct 1, 2016 See explanation... Explanation: Starting from: cos2(x) + …

WebCalculus. Solve for ? tan (x)=-1/3. tan (x) = − 1 3 tan ( x) = - 1 3. Take the inverse tangent of both sides of the equation to extract x x from inside the tangent. x = arctan(−1 3) x = … WebFinal answer. Step 1/3. Given trigonometric equations, c) 2 cos 2 θ − 7 cos θ = − 3. Add 3 to both sides of the equation. 2 cos 2 ( θ) − 7 cos ( θ) + 3 = 0. Factor by grouping. ( 2 cos ( θ) …

Webd) sen 30° − 2 tan 30° + 5 sec 60° e) tan 30° cot 60° − sec 45° cos 45° f) 1 − 2 sen30° + 3 sec 30° + tan 45° g) (sen230°) cot 45° − 2 tan2 60° csc 30° h) √3 tan 60° + √2 csc 45° − sec 60° Comprueba: a) sec245° = 1 + tan245° b) (1 + tan 60°)cos260° = 1 c) 1 − 2sen230° = cos260° d) tan 45° =sen 45°cos45 ...

WebSolution: We know that tan2x = 2tan x / (1 − tan 2 x). If tan x = 4/3, we have tan 2 x = 16/9. tan2x = 2tan x / (1 − tan 2 x) = 2 (4/3)/ (1 - 16/9) = (8/3)/ (-7/9) = -24/7 Answer: tan2x = -24/7 Example 2: Find the value of tan2x if sin x = 12/13 and cos x = 5/13 Solution: We know that tan2x = sin 2x/ cos 2x = 2 sin x cos x / (cos 2 x - sin 2 x)

WebMar 22, 2024 · Ex 2.1, 14 (Method 1) Find the value of tan−1 √3 – sec−1 (–2) is equal to π (B) – π/3 (C) π/3 (D) 2π/3 Solving tan−1 √𝟑 Let y = tan−1 √3 tan y = √3 tan y = tan (𝝅/𝟑) ∴ y = 𝝅/𝟑 … mohammed reveshiWebmath work 315 section summary of curve sketching 30 _10 figure figure so far we have been concerned with some particular aspects of curve sketching: domain, mohammed rezwanWebmat 2010 fall 20 final exam key.pdf - MAT 2010 Fall’20 1. Apply the definition of the derivative: x2 x h 2 − 1 x h 2 3 x − x2 3 x h mohammed rizwan newsWebThis problem has been solved! You'll get a detailed solution from a subject matter expert that helps you learn core concepts. See Answer. Question: Find the exact value of each … mohammed reza lawyerWebMar 17, 2024 · Solution For Q.9. tan−13 −sec−1(−2) is equal to: [HBSE 2024; NCERT EX. 2.1, Q.1. The world’s only live instant tutoring platform. Become a tutor About us Student login Tutor login. Login. Student Tutor. Filo instant Ask button for chrome browser. Now connect to a tutor anywhere from the web ... mohammed reza hedayatiWebQuadratic equation. x2 − 4x − 5 = 0. Trigonometry. 4sinθ cosθ = 2sinθ. Linear equation. y = 3x + 4. Arithmetic. 699 ∗533. Matrix. mohammed saeb shakir pa-cWebSolve for a tan(a)=1/3. Step 1. Take the inverse tangent of both sides of the equation to extract from inside the tangent. Step 2. ... Tap for more steps... Evaluate. Step 3. The … mohammed rohail