Get the digits of a number java

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WebJan 20, 2016 · I want my program to get all the even digits from a number input. Then multiply those with digits with 2. If the result is a two digit number, add them. At the end i want it to give me the sum of all the even digits. public class evenplaceadd { WebMay 5, 2024 · Your "math" is working correctly. The one thing you can: compute the length (number of digits) within your number upfront, to avoid "iterating" the number twice - so you can determine if that number of digits is even or odd without "iterating" the number:. int n = 1234; int length = (int)(Math.log10(n)+1); should give you 4 for 1234, and 5 for …

How to sum digits of an integer in java? - Stack Overflow

WebApr 1, 2012 · To determine the place of the number, you can convert the integer to a String, and get the length of it. For example... int [] a= {123,342,122,333,9909}; int maxNumber = a.getMax (); // will return '9909' int numberPlace = (new Integer (maxNumber)).toString ().length; // will return '4' WebNov 2, 2024 · Using Integer.toString Function (Using inbuilt Method) Using modulo operator. Approach 1: Using Integer.toString Method. This method is an inbuilt method present already in the directory of java which returns the string object. This string object … The java.lang.Integer.toString(int a) is an inbuilt method in Java which is used to … sleep quest order form

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WebJun 17, 2013 · I need to define the last digit of a number assign this to value. After this, return the last digit. My snippet of code doesn't work correctly... Code: public int lastDigit (int number) { String temp = Integer.toString (number); int [] guess = new int [temp.length ()]; int last = guess [temp.length () - 1]; return last; } Question: WebFeb 12, 2014 · long num = 2432902008176640000L; int n = 4; long first_n = (long) (num / Math.pow (10, Math.floor (Math.log10 (num)) - n + 1)); I am assuming you mean factorial of a number. Just convert the number into a string and use substring method to get first 4 digits only. fact is the factorial value. Web1 day ago · JavaScript Program to Check if all array elements can be converted to pronic numbers by rotating digits - Pronic numbers are also known as rectangular numbers, … penley phoenix cabernet sauvignon 2019

How to get the number of decimal digits from a double in Java?

Getting each individual digit from a whole integer - Stack Overflow

WebMar 13, 2011 · You can either use the following: Integer.parseInt ("123".substring (0, 2)) OR int temp = 12345678; int result = temp / (int)Math.pow (10, (int) (Math.log10 (temp) - 1)) Share Improve this answer Follow edited Nov 7, 2024 at 6:54 Jacob Ahlberg 2,242 6 22 44 answered Nov 7, 2024 at 6:04 Stark 21 2 Add a comment 0 public class ExtractingDigits { WebJul 22, 2015 · 1. This method below allows you to get a specific number from a int value based on a specific index. public static int getSpecificNum (int number, int index) { int … sleep resources nhsWebOct 4, 2016 · String numToString = ""; while (num > 0) { int lastDigit = num % 10; numToString +=lastDigit+" + "; sum = sum + lastDigit; num = num/10; } //eliminate the last + sign numToString = numToString.substring (0,numToString.lastIndexOf ("+")).trim (); System.out.println (numToString +" = " +sum); } } Share Improve this answer Follow penman emt acronym

"WebFor efficiency, we'll store not real decimal digits, but work in base 1 000 000 000 = 10^9 < 2^30. This fits in a Java int (up to 2^31 or 2^32), and the product of two such digits fits nicely in a Java long. final static int BASE = 1000000000; final static int BASE_DECIMAL_DIGITS = 9; Then the digits-array: private int[] digits; " - Get the digits of a number java

Get the digits of a number java

java - Extracting each digit in an int - Stack Overflow

WebNov 26, 2024 · A Computer Science portal for geeks. It contains well written, well thought and well explained computer science and programming articles, quizzes and practice/competitive programming/company interview Questions. WebI have JPA entity as And then Repository as (adsbygoogle = window.adsbygoogle []).push({}); Now, when I run it then I get following exception: And stored procedure is: It is running against Oracle database. Can someone please help me understand even though I have correct parameter numbers

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WebFeb 16, 2011 · The sound and perfect way to get decimal part of float and double data types, is using with String like this code: float num=2.35f; String s= new Float (num).toString (); String p=s.substring (s.indexOf ('.')+1,s.length ()); int decimal=Integer.parseInt (p); Share Follow answered Aug 18, 2016 at 14:59 Gholamali Irani 4,361 6 27 59 Add a comment 4 WebOct 10, 2016 · 8. The "hint" is actually a nearly direct explanation of how to do what you need to do: dividing in integers by ten gets rid of the last digit, while obtaining modulo ten gives you the last digit: int x = 12345; int lastDigit = x % 10; // This is 5 int remainingNumber = x / 10; // This is 1234. Do this in a loop until the remaining number is zero.

WebDec 19, 2015 · 6. I have a huge double that i want to get the first 2 decimal digits as float from. Here is an example: double x = 0.36843871 float y = magicFunction (x) print (y) Output: 36. If you don't understand feel free to ask questions. java. WebMay 26, 2012 · int num1 = (int) ( (Math.random ()*100000)+1); System.out.println ("Randomed number: " + num1); while ( (num1/10)>0) num1 = num1/10; System.out.println ("Left digit: " + num1); and it works fine for me Share Improve this answer Follow answered May 26, 2012 at 11:51 Pshemo 122k 25 183 266

WebJan 6, 2014 · Cast the integer to a string and get its last two characters. int b = 1909; String bStr = String.valueOf (b); System.out.print (bStr.substring (bStr.length ()-2)); This works only for integers with at least two digits though. So you might want to make sure you won't get a one-digit integer. WebJul 14, 2010 · 11 Answers Sorted by: 160 How about: String numbers = text.substring (text.length () - 7); That assumes that there are 7 characters at the end, of course. It will throw an exception if you pass it "12345". You could address that this way: String numbers = text.substring (Math.max (0, text.length () - 7)); or

WebSep 11, 2014 · Get the portion of the string after the decimal place and count the numbers until you get to a 0. There are corner cases but you can take care of that. One thing though, some numbers cannot be represented exactly, such as 4/3, so the number of the decimal places theoretically is infinite.

WebWhat is best way to achieve this in Java? I have tried like this: Double d = 1.15; String str = d.toString (); int len = str.substring (str.indexOf (".")).length () - 1; int i= (int) (d * (long)Math.pow (10,len) % (long)Math.pow (10,len)); But I didn't get the proper answer because when I convert d.toString () the answer is 14.999999999999986. java penmaen industrial estate pontllanfraithWebJan 26, 2024 · Perhaps the easiest way of getting the number of digits in an Integer is by converting it to String, and calling the length () method. This will return the length of the String representation of our number: int … sleepphones directionsWebFeb 24, 2024 · Logic is if you add any number by 9, resulting addition of digit will result in the same number. Example: 6 + 9 = 15 then 1 + 5 = 6 (again you got 6). In case of decimal point, remove it and add resulting digits. Below code does the trick: i % 9 == 0 ? 9 : i % 9 Share Improve this answer edited Nov 29, 2024 at 17:59 answered Aug 20, 2024 at 8:42 penmarch le guilvinecWebDec 31, 2024 · The task if for you get create an algorithm that finds what two numbers in the given array of numbers that equal targetSum. After a few hours I understood clearly the algorithm and familiar with ... penlar pharmacy lawrenceville njWebNov 2, 2013 · Right now I'm using something like this: Basically the program is supposed to print X (right most digit of a #) to X decimal places for example: entered 3.56, should display 0000000000000003.560 sleep place novice mattressesWebA complex number is a number that can be expressed in the form a + bi, where a and b are real numbers and i is the imaginary unit, defined as i = sqrt(-1). The number a is called the real part of the complex number, and b is called the imaginary part. For example, the complex number 3 + 4i has a real part of 3 and an imaginary part of 4. penman paper journalWebJul 20, 2011 · String num = number + ""; return num.substring (0, numDigits); If you need the number itself you can do int div = Math.pow (10, numDigits); while (number / div > 0) number /= 10; Share Improve this answer Follow answered Jul 20, 2011 at 6:16 Jesus Ramos 22.8k 10 56 88 Add a comment Your Answer Post Your Answer penlac nail lacquer goodrx